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Phee's Riddle thread


phee

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i think i got it! Cher was standing infront of rev, with 2 already in hand, which technically would make those in front of rev.. then she took one, and walked off... hence taking 3 (2 of which she already had in possession of) wich left rev with only 9

I like that answer... not what I was looking for... but very good thoughts...

*CLICK HERE FOR HINT*

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hm.. roman numerals probably XII equals 12.. take one away XI would be 11 still.. but flipped around it would be IX making 9... so he could have 9 or 11, depending on the persective of view... am i at least on the right path here??

Sort of...

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ok ok,, alphabet time..

A=1

B=2

C=3 and so forth.. so I=9 and L=12

copsticks are at an angle like this.. |_ making an L=12, cher takes the _ one leaving the | making 9!

Thinking too hard...

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|\|

|\

|\|

E

E making 4 by it's self... counting the red one, totaling 12.. remove the red one, and it spells out "NINE"

WE HAVE A WINNER!!!

An easer one:

know_buddy_cares is condemned to death. He must choose between three rooms. The first is full of raging fires, the second is full of assassins with loaded guns, and the third is full of lions that haven't eaten in 3 years. Which room is safest for him?

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Correct.... I am not sure if KBK is correct because I am not sure what he means....

Suppose Rayne wants to send in the mail a valuable thing to AstralCrux. She has a box which is big enough to hold the thing. The box has a locking ring which is large enough to have a lock attached and Rayne has several locks with keys. However, AstralCrux does not have the key to any lock that Rayne has. Rayne cannot send the key in an unlocked box since it may be stolen or copied. How does Rayne send the valuable object, locked, to AstralCrux - so it may be opened by her?

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use a combination lock?

I think that is a better answer then the actual one to be honest....

but

"Rayne has several locks with keys" She does not have, or have means of getting... (because of some stupid reason) a combination lock.

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How's the key for a different lock going to unlock the 1st lock...can't you send them separately?

I think you have defeated this one...

The actual answer is you send the box with your lock... they receive the box and send it back with a lock on their own, you receive the box unlock yours, send it back, they remove their lock and viola....

I think your answers were both right though....

ahem....

Moving on:

Angel of Death and DeadBurgerKing play five games of checkers. Each of them wins the same number of

games. There are no ties. Explain this.

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